czech:Kleinova láhev je těleso,ve kterém nelze přejít přes okraj. Technicky vzato má jen jednu stranu. V knize Hravá matematika od Radka Chajdy jsem našel otázku: lze do Kleinovy láhve něco nalít? Ano lze do ní něco nalít a ještě není potřeba víčko.

Lukáš HOZDA 1.11.2009

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Image:Klein bottle.svg

Ek, die outeursreghouer van hierdie werk, stel dit hiermee in die publieke domein vry. Dit geld wêreldwyd. In sommige lande is dit dalk nie wettiglik moontlik nie. Indien so: Ek verleen aan enigiemand die reg om hierdie werk te gebruik vir enige doel, sonder voorwaardes, tensy sulke voorwaardes deur die wet vereis word.

This immersion of the Klein bottle into R³ is given by the following parameterization. Here the parameters u and v run from 0 to 2π and r is a fixed positive constant.

For ${\displaystyle 0\leq u<\pi }$:

${\displaystyle x=6\cos u(1+\sin u)+4r\left(1-{\frac {\cos u}{2}}\right)\cos u\cos v}$

${\displaystyle y=16\sin u+4r\left(1-{\frac {\cos u}{2}}\right)\sin u\cos v}$

${\displaystyle z=4r\left(1-{\frac {\cos u}{2}}\right)\sin v}$

For ${\displaystyle \pi \leq u<2\pi }$:

${\displaystyle x=6\cos u(1+\sin u)-4r\left(1-{\frac {\cos u}{2}}\right)\cos v}$

${\displaystyle y=16\sin u\,}$

${\displaystyle z=4r\left(1-{\frac {\cos u}{2}}\right)\sin v}$

KleinBottle[r_:1] =
 Function[{u, v},
   UnitStep[Sin[u]]
   {
       6 Cos[u](1 + Sin[u]) + 4r(1 - Cos[u]/2) Cos[u]Cos[v],
       16 Sin[u] + 4r(1 - Cos[u]/2) Sin[u]Cos[v],
       4r(1 - Cos[u]/2) Sin[v]
   }
   + (1 - UnitStep[Sin[u]])
   {
       6 Cos[u](1 + Sin[u]) - 4r(1 - Cos[u]/2) Cos[v],
       16 Sin[u],
       4r(1 - Cos[u]/2) Sin[v]
   }
 ]

 ParametricPlot3D[Evaluate[KleinBottle[][u, v]], {u, 0, 2Pi}, {v, 0, 2Pi},
   PlotPoints -> {50, 19}, Boxed -> False, Axes -> False,
   ViewPoint -> {0.454, -2.439, -2.301}]